0,8x^2+4x+5=0

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Solution for 0,8x^2+4x+5=0 equation: 



0.8x^2+4x+5=0

a = 0.8; b = 4; c = +5;
Δ = b2-4ac
Δ = 42-4·0.8·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{1.6}=-2+0.8/1.6$

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